Some characteristics of logarithms will be explaned, first a to the power m times a to the power of n equals a to the power m sum n, second a to the power of m over a to the power of n equalso a to the pow
er of m minus n, third, logarith a base b equals n so b equals a to the power of n, fourth, logarithm a base g equals x so a equals g to the power of x, fifth, logarithm b base g equals y so b equals g to the power of y.Exercise,calculate this question...
Logarithm a times b base g?
We give example that logarithm a base b equals x so a equals g to the power of x, logarithm b base g equals y so b equals g to the power y and some times a times b equals g to the power of x times g to the power of y so a times b equals g to the p
ower of x sum y. Than logarithm a times b base g equals logarithm g to the power of x sum y equals all of x sum y to the power g logarithm g, and we give example logarithm g equals one and the solution is x sum y.And the last, is logarithm all of a times b base g logarithm a base g sum logaritm b base g.We direct to step soon,
a over b equals g to the power of x over g to the power y.a over b equals g to the power all of x minus y,and logarithm all of a over b base g equals logarithm g bto the power all of a minus b base g, than logarithm a over b base g equals all of x minus y than logarithm all of a over b base g equals logarithm a base g minus logarithm b base g.
2. Why is root of two a irasional numeral
Irasional numeral is real numeral can not be over.
Irrasional numeral can't be seen as over b with a and b are integer and b isn't zero.
So irrasional numeral is not rasional numeral. In here,root of two is a irrasional numeral because root of two can't be over as a over b. Value of root of two is one point four-0ne-four-two-one-three-five-six-two-three-seven-three-zero-nine-five-zero-four-eight-eight-zero-one-six-eight-eight-seven-two-four-zero-nine-six-...etc.
3. What is the value betwen y equals x to the power of two minus one and x to the power two times y to the power two equals thirty.
Solution is....
x to the power two times y to the power two equals thirty is changed become y equals root all of thirty minus x to the power two as y one and y equals x to the power two minus one as y two.
y one as left section and y two as right section.
y one equals y two.
Than x to the power of two minus one equals root all of thirty minus x to the power two.
left section and right section are to power two.
Left section became x to the power four minus two power two times one equals thirty minus x to the power two.Than x to the power four minus x to the power two minus equals twenty nine equlas zero.
To finish this question, we use the ABC theorem.
